Question

what mass of lead(II) chloride would be produced when a solution containing o.3 mol of sodium chloride is mixed with a solution containing excess lead(II) nitrate? The equation for this reaction is: Pb(NO3)2(aq) -> PbCl2(s)+2NaNO3(aq)

Answer 1

Answer:

4.00 gram of sodium chloride was added to a solution containing excess lead  

rection.

Explanation:

                     2NaCl(s)+2Pb(NO3)2(aq)⇒2NaNO3(aq)+2PbCl2(s)Calculate the masnitrate,lead chloride was precipitated according tothe following    s of lead chloride that can be recovered assuming a 90% recovery