What mass of Magnesium is required to react with 12 g of sulphur to form Magnesium sulphide
Answers
Answer:-
16g of Magnesium is required to react with 12g of Sulphur to form Magnesium Sulphide.
Explanation:-
The balanced chemical equation for the reaction is :-
Mg + S → MgS
________________________________
• Molar mass of Magnesium = 24 g/mol
• Molar mass of Sulphur = 32 g/mol
Now, from the balanced equation :-
∵ 32g of S reacts with 24g of Mg.
∴ 12g of S will react with :-
= 12×32/24
= 32/2
= 16g of Mg
Some Extra Information:-
Calculations based on the quantatitve relationship bewteen the reactants and the products are referred to as stoichiometry.
In order to solve problems based on chemical calculations, the steps are :-
(i) Write the balanced chemical equation.
(ii) From the chemical equation write the
molar ratio bewteen given and
required substance.
(iii) Convert these moles into the desired
parameters such as mass and volume.
(iv) Calculate the final result by applying
unitary method.
Explanation:
Answer:-✍️✍️
16g of Magnesium is required to react with 12g of Sulphur to form Magnesium Sulphide.
Explanation:-
The balanced chemical equation for the reaction is :-
Mg + S → MgS
________________________________
• Molar mass of Magnesium = 24 g/mol
• Molar mass of Sulphur = 32 g/mol
Now, from the balanced equation :-
∵ 32g of S reacts with 24g of Mg.
∴ 12g of S will react with :-
= 12×32/24
= 32/2
= 16g of Mg
Some Extra Information:-
Calculations based on the quantatitve relationship bewteen the reactants and the products are referred to as stoichiometry.
In order to solve problems based on chemical calculations, the steps are :-
(i) Write the balanced chemical equation.
(ii) From the chemical equation write the
molar ratio bewteen given and
required substance.
(iii) Convert these moles into the desired
parameters such as mass and volume.
(iv) Calculate the final result by applying
unitary method.