Question

What mass of Mg(NO3)2 is present in 145 mL of a .150 M solution of Mg(NO3)2?

Answer 1

Apply Molarity formula.

Molarity= Moles/ Vol in dm³ or Liter

Molarity = (Mass/Molar mass)/ Vol in dm³

.150 = (Mass/148.3)/0.145L

Solve it further