Question

what mass of MgSO4 required to prepare 25% (mass%) solution in 200 of water​

Answer 1

Answer:

I am taking mass of water as 200 g as it is not clear in the question.

Explanation:

Mass of solvent= 200g

mass of MgSO4=? {let it be x}

mass percentage=25%

mass percentage= [mass of solute/mass of solvent]X100

                25              =[x/200] X 100

                25               =x/2

                50               =x

So, the mass of MgSO4 required is 50g