what mass of N2 will be required to produce 34.0 g of NH3 by the reaction N2+3H2->2NH3
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Answer:
From the eq.,
28g of N2 produces 34g of NH3
As mass of 1 n atom =14g
And mass of 1 molecule (2 atoms) of N2=2×14=28g
mass of 1 moles of NH3=14+3=17g
Hence, mass of 2 moles of NH3=17×2=34g
therefore mass of N2 =28g
Explanation:
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