Question

What mass of Na.So, 7H.O contains exactly 6.023 x 10 atoms of oxygen​

Answer 1

Answer:

i hope it will help you mark as Brainliest and pls follow me

Explanation:

1 molecule of Na₂SO₄.7H₂O contains 11 atoms of oxygen.

Similarly,

1mole of Na₂SO₄.7H₂O contains 11moles of oxygen.

We know 1mole contains 6.022 x 10²³ particles,

so,       0.1 moles contain 6.022 x 10²² particles.

Given that there are 6.022 x 10²² atoms of oxygen.

The above statement indicates there are 0.1 moles of oxygen.

We know,

       11 moles of oxygen atoms are present in 1mole of Na₂SO₄.7H₂O

so,0.1moles of oxygen atoms are present in 0.009moles of Na₂SO₄.7H₂O

Mass of 0.009 moles of Na₂SO₄.7H₂O = 0.009 x 268 = 2.412 grams

Hence 2.412 grams of Na₂SO₄.7H₂O contains 6.022 x 10²² oxygen atom