Question

What mass of NaCl is needed to make a 1.5 m solution using 300 g of solvent​

Answer 1

Answer:

mass of nacl= molar mass *no of molecules

Answer 2

Answer:

 $26.3g$ of sodium chloride is required in a 1.5 m solution.

Explanation:

First, we have to find out the moles of solute ($NaCl$) present in the solvent using the molality formula.

$molality = \frac{moles of solute}{weight of solvent}$

We have,

The molality of the solution = 1.5 m

The weight of solvent = 300g = 0.3 kg

$1.5 = \frac{moles of solute}{0.3}$

$0.45mol = moles of solute$

0.45 mol of $NaCl$

Now using the mole formula we can find out the mass of $NaCl$ required.

$mole = \frac{mass}{molar mass}$

The moles of $NaCl$ - 0.45 mol

The molar mass of $NaCl$ - 58.5 g/mol

$0.45 = \frac{mass}{58.5}$

$0.45 * 58.5 = mass$

$26.3g$ of $NaCl$

Conclusion:

$26.3 g$ of $NaCl$ is required.