Question

what mass of NaCl is required to prepare 600 ml of 0.1 M solution​

Answer 1

Explanation:

$\huge\bf{\mid{\overline{\underline{ANSWER:-}}\mid}}$

$Molarity = \frac{No. \: of \: moles \: of \: solute}{Volume \: of \: solution \: (in \: L) } \\ \\ 0.1 = \frac{n}{0.6} \\ \\ \huge\boxed{n = 0.06 moles}$