What mass of nacl would contain the same total number of ions as 245 gram of mgcl2?
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Answered by
35
Molar mass of MgCl2 = 24 + 35.5x2 = 95g/mol
Number of moles of MgCl2 in 245 g = 245/95 = 2.579 moles
1 ion of Mg and 2 ions of Cl
Number of ions = 3 x 2.579 x 6.022x10^23
= 4.659 x 10^24
Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
1 Na+ ion and 1 Cl- ion
58.5 g NaCl contain = 2 x 6.022 x 10^23 = 1.2044x10^24
What mass of NaCl will contain 4.659 x 10^24 ions?
Mass of NaCl = (4.659 x 10^24)/ (1.2044x10^24) * 58.5
= 226.3 g
Number of moles of MgCl2 in 245 g = 245/95 = 2.579 moles
1 ion of Mg and 2 ions of Cl
Number of ions = 3 x 2.579 x 6.022x10^23
= 4.659 x 10^24
Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
1 Na+ ion and 1 Cl- ion
58.5 g NaCl contain = 2 x 6.022 x 10^23 = 1.2044x10^24
What mass of NaCl will contain 4.659 x 10^24 ions?
Mass of NaCl = (4.659 x 10^24)/ (1.2044x10^24) * 58.5
= 226.3 g
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