Question

What mass of nacl woupd be decomposed by 9.8 of h2so4 is 12g of sodium bi sulphite and 2.75 g of hcl were produced in a reaction assuming that law of conservation of mass is true

Answer 1

Nacl+H2 So4-----NaHSO3+ HCl
x. 9.8. 12g 2.75g
X=12+2.75-9.8=14.75-9.8= 4.95. Mean NaCl required 4.95g to veryfy law of conservation of mass.

Answer 2

Answer: The mass of NaCl that would be decomposed will be 4.95 grams.

Explanation:

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

The chemical equation for the reaction of sodium chloride and sulfuric acid follows:

$NaCl+H_2SO_4\rightarrow NaHSO_4+HCl$

Let the mass of sodium chloride be 'x' grams

We are given:

Mass of sulfuric acid = 9.8 grams

Mass of sodium bi sulfite = 12 grams

Mass of hydrochloric acid = 2.75 grams

Total mass on reactant side = 9.8 + x

Total mass on product side = 12 + 2.75 = 14.75 g

So, by applying law of conservation of mass, we get:

$9.8+x=14.75\\\\x=4.95g$

Hence, the mass of NaCl that would be decomposed will be 4.95 grams.