Question

what mass of napthalene should be dissolved in 200g of octave for lower the vapour pressure of octave by 20%​

Answer 1

Answer:

The mole fraction of the solute is 0.20, so the mole fraction of octane is 0.80.

(200 g C8H18) / (114.2285 g C8H18/mol) = 1.7509 mol octane

(1.7509 mol octane) / (0.80) = 2.1886 mol total

(2.1886 mol total) - (1.7509 mol octane) = 0.4377 mol C10H8

(2.1886 mol total) - (1.7509 mol octane) = 0.4377 mol C10H8(0.4377 mol C10H8) x (128.1705 g C10H8/mol)

= 56.1 g C10H8 •••••answer

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