Question

What mass of NH3 will contain same number of molecules as that in 36 grams of H2O?

Answer 1

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Answer 2

Given : Amount of water (H2O) = 36g

To find : Mass of NH3 will contain the same number of molecules as that in 36 grams of H2O

Solution :

No. of moles : given mass of the substances / molar mass of the substances.

No. of moles : given mass of the substances / molar mass of the substances.∴ No. of moles of water = 18 / 36 = 2

No. of moles : given mass of the substances / molar mass of the substances.∴ No. of moles of water = 18 / 36 = 2Also, No. of molecules = No. of moles x Avogadro's Number

No. of moles : given mass of the substances / molar mass of the substances.∴ No. of moles of water = 18 / 36 = 2Also, No. of molecules = No. of moles x Avogadro's NumberNo. of molecules of H₂O = (2 x 6.022 x 10²³) = 12.022 x 10²³

No. of moles : given mass of the substances / molar mass of the substances.∴ No. of moles of water = 18 / 36 = 2Also, No. of molecules = No. of moles x Avogadro's NumberNo. of molecules of H₂O = (2 x 6.022 x 10²³) = 12.022 x 10²³So, No of molecules of NH₃ = 12.022 x 10²³ (Given)

No. of moles : given mass of the substances / molar mass of the substances.∴ No. of moles of water = 18 / 36 = 2Also, No. of molecules = No. of moles x Avogadro's NumberNo. of molecules of H₂O = (2 x 6.022 x 10²³) = 12.022 x 10²³So, No of molecules of NH₃ = 12.022 x 10²³ (Given)∴No. of moles of NH₃ = 12.022 x 10²³ / 6.022 x 10²³ = 2

No. of moles : given mass of the substances / molar mass of the substances.∴ No. of moles of water = 18 / 36 = 2Also, No. of molecules = No. of moles x Avogadro's NumberNo. of molecules of H₂O = (2 x 6.022 x 10²³) = 12.022 x 10²³So, No of molecules of NH₃ = 12.022 x 10²³ (Given)∴No. of moles of NH₃ = 12.022 x 10²³ / 6.022 x 10²³ = 2Mass of NH₃ = No. of moles of NH₃ x Molar mass of NH₃ = (2 X 17) = 34g

No. of moles : given mass of the substances / molar mass of the substances.∴ No. of moles of water = 18 / 36 = 2Also, No. of molecules = No. of moles x Avogadro's NumberNo. of molecules of H₂O = (2 x 6.022 x 10²³) = 12.022 x 10²³So, No of molecules of NH₃ = 12.022 x 10²³ (Given)∴No. of moles of NH₃ = 12.022 x 10²³ / 6.022 x 10²³ = 2Mass of NH₃ = No. of moles of NH₃ x Molar mass of NH₃ = (2 X 17) = 34gHence, the mass of NH3 will contain the same number of molecules as that in 36 grams of H2O is 34g.

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