Question

What mass of nitrogen has the same number of particles as 320g of oxygen gas?

Answer 1

Answer:

According to Avogadro's Law, “Equimolar concentrations of all substances at equal conditions of temperature and pressure contain equal number of molecules.”

For both of these gases to have the same number of molecules they would have to consist of equal moles.

Number of moles of a substance is obtained by dividing the mass of substance needed by the molecular mass of the substance.

Molecular mass of Nitrogen Gas N2 = 28 g

Number of moles of Nitrogen in 56 g = 56/28 = 2 mol

So number of moles of Oxygen is also 2.

Mass of 2 mole Oxygen is =

Number of moles × Molecular Mass of Oxygen Gas O2

= 2 × 32

= 64 g

Explanation:

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Answer 2

Given mass = 320 g of Oxygen Gas

Molar mass of O2 (Gas) = 32 g

since,

No. of molecules = (No. of moles) × Avogadro no,

⟹ No. of molecules = (Given mass/Molar mass)(Avogadro constant)

⟹ No. of molecules = (320 g ÷ 32 g)(6.022 × 10²³)

⟹ No. of molecules = 10(6.022 × 10²³)

= 6.022 × 10²⁴ of O2

We also know,

Molar mass of N = 14 g

since,

No. of molecules = (Given mass/Molar mass)(Avogadro constant)

[Let given mass be = x]

⟹ 6.022 × 10²⁴ = x/14 × 6.022 × 10²³

⟹ x/14 × [(6.022 × 10²⁴) ÷ (6.022 × 10²³)]

⟹ x/14 = 10

⟹ x = 10 × 14

⟹ x = 140 g

∴ 140 grams of Nitrogen atoms has the same number of particles as 320 g of Oxygen Gas.