What mass of nitrogen will be required to produce 6.023*10*24 molecules of ammonia by the following reaction ?N2+3H2=2NH3
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we have,
no.of molecules=n*No
=>6.023*10^24=n*60.23*10^23
=>n=10
from the reaction,
1moles of N2 produce 2mole of NH3
therefore,
10moles of NH3 required=5moles N2
hence,
weight=M*5
w=28*5
=>w=140g
no.of molecules=n*No
=>6.023*10^24=n*60.23*10^23
=>n=10
from the reaction,
1moles of N2 produce 2mole of NH3
therefore,
10moles of NH3 required=5moles N2
hence,
weight=M*5
w=28*5
=>w=140g
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