What mass of non volatile solute urea needs to be dissolved in 100g of water in order to decrease the vapour pressure of water by 25%? What will be the molality of the solution?
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Answer:
Using Raoult's law in the following form,
P
0
P
0
−P
s
=
W×m
w×M
If P
0
=100 mm, then P
s
=75 mm
100
100−75
=
100×60
w×18
w=83.33 g
Molality =
m×W
w×1000
=
60×100
83.33×1000
=13.89 m
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