Question

what mass of oxygen contain the same of molecule as 42 g of nitrogen?
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Answer 1

Step-by-step explanation:

The molecular formula of calcium nitrate is Ca(NO3)2

So,molar mass of calcium nitrate = 40+(14+16×3)2=164g

28g nitrogen attached to 40g calcium

Therefore,42g nitrogen attached to 40×42/28 = 60g

Answer 2

Step-by-step explanation:

Given: 42 g of N2

Solve for O2 mass that contains the same number of molecules to 42 g of N2.

Solve for the number of moles in 42 g of N2

1 mole of N2 = (14 * 2) g = 28 g so the number of moles in 42 g of N2 is equal to 42 g / 28 g per mole = 1.5 moles

Solve for mass of 1 mole of oxygen

1 mole of O2 = 16 g * 2 = 32 g per mole

Solve for the mass of 1.5 moles of oxygen

mass of 1.5 moles of O2 = 32 g per mole * 1.5 moles

mass of 1.5 moles of O2 = 48 g

So 48 g of O2 contains the same number of molecules as 42 g of N2