Question

what mass of oxygen is combined with 9.02 gram of sulphur in sulphur dioxide

Answer 1

Answer:see the attachment

Good luck

Explanation:

Answer 2

Answer:

The oxygen's mass combined with sulphur of $9.02g$ in sulphur dioxide is $8.96g$.

Explanation:

Given,

The mass of sulphur in sulphur dioxide, $SO_{2}$ = $9.02g$

The mass of oxygen combined with sulphur in sulphur dioxide =?

As we know,

• $S + O_{2} \rightarrow SO_{2}$

Here, one mole of sulphur combined with 1 mole of oxygen to form $SO_{2}$.

Therefore,

• Number of moles of sulphur = number of moles of oxygen

As we know,

• The molar mass of sulphur = $32g/mol$.

Now, we have to calculate the number of moles by the equation given below:

• Number of moles = $\frac{Given mass}{Molar mass}$ = $\frac{9.02}{32}$ = $0.28 mol$

Now, we have to calculate the mass of oxygen combined with sulphur:

As we know.

• The molar mass of $O_{2}$ = $32g/mol$

• Number of moles =  $\frac{Mass}{Molar mass}$
• Mass = $0.28\times 32$ = $8.96g$

Hence, the mass of oxygen = $8.96g$.