What mass of Oxygen reacts with 9.2g of Sodium? using this equation: 4Na + O2 = 2Na2O
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Answer:
16 is correct answer according to me
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Molar mass of Na = 23
Molar mass of O2 = (16x2) = 32
Molar mass of Na2O = (23x4) + 16 = 108
According to the equation:
(4 x 23) + (1 x 32) → 2(108)
92 g + 32 g → 216 g
If 92 g Na reacts with 32 g O2
Then 9.2 g Na will react with (32/10) g of O2 = 3.2g
Answer: 3.2g. Hope this helped. Please make me as the brainliest :)
Molar mass of O2 = (16x2) = 32
Molar mass of Na2O = (23x4) + 16 = 108
According to the equation:
(4 x 23) + (1 x 32) → 2(108)
92 g + 32 g → 216 g
If 92 g Na reacts with 32 g O2
Then 9.2 g Na will react with (32/10) g of O2 = 3.2g
Answer: 3.2g. Hope this helped. Please make me as the brainliest :)
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