Question

What mass of silver chloride can be prepared by the reaction of 100.0 ml of 0.20 m silver nitrate?

Answer 1

Total volume of solution = 100.0 ml + 100.0 ml = 200.0 ml

= 0.2000 L

Molarity = moles / L

Molarity Cl- = 0.010 mole / 0.2000 L

= 0.050 M

Molarity Ca2+ = 0.0050 mol / 0.2000 L

= 0.025 M