What mass of silver chloride precipitate will be produced if 25 cm3 of 0.1mol/dm3 silver nitrate is added to excess sodium chloride solution?
NaCl + AgNO3 → AgCl + NaNO3
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Explanation:
equivalent of silver nitrate = equivalent of silver chloride
here molarity in other units we shall convert it into normal ones
1m^3 = 1000 lt
10^-1 m^3 = 100 lt
divide 0.1 by 100
0.001
which molarity of solution
mvf=moles*f*1000
0.001*25*1=moles*1*1000
moles = 25*10^-6
w/143.5 = 25*10^-6
w=3587.5*10^-6
w=3.6*10^-3
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