Chemistry, asked by heydf, 11 months ago

what mass of silver nitrate will 5.85g of sodium chloride to produce 14.35g of silver chloride and 8.5g of silver nitrate if the law of conservation of mass is true??0​

Answers

Answered by Arcel
0

17 Grams

Given:

Mass of Sodium Chloride = 5.85 grams

Mass of Silver Chloride which is produced = 14.35 grams

Mass of Silver Nitrate which is produced = 8.5 grams

To Find:

Mass of Silver Nitrate if the law of conservation of mass is true.

Calculating:

The Equation in words

Silver Nitrate + Sodium Chloride -------------> Sodium Nitrate + Silver Chloride

This is a double displacement reaction.

AgNO3 + NaCl --------------> NaNO3  +     AgCl

5.85 g                                     8.5 g      14.35 g

The law of conservation of mass tells us that the total number of reactants is equal to the total number of products.

In a chemical reaction the mass of the substances in reactant side is always equal to the mass of the substances in the product side.

Adding masses in the product side we get:

= 8.5 g + 14.35 g

= 22.85 grams

The mass of the reactant side = 5.85 grams

So to find the mass of Silver Nitrate the formula we are going to use:

= Mass of Product Side - Mass of Sodium Chloride

Substituting the values into this formula we get:

= 22.85 - 5.85

= 17 grams

Therefore, the mass of silver nitrate is 17 grams if the law of conservation of mass is true.

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