Question

what mass of silver nitrate will react with 11.7 grams of sodium chloride to produce 28.7 grams of silver chloride and 17 gram of sodium nitrate if law of conservation of mass holds true.


please answer fast​

Answer 1

Answer:-

Required mass of Silver Nitrate is 34 grams .

Explanation:-

We have :-

• Mass of Sodium Chloride = 11.7 g

• Mass of Silver Chloride = 28.7 g

• Mass of Sodium Nitrate = 17 g

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The balanced chemical equation for the given reaction is :-

AgNO₃ + NaCl → + AgCl + NaNO₃

In the given chemical equation :-

→ Silver Nitrate [AgNO₃] and Sodium Chloride [NaCl] are reactants.

→ Silver Chloride [AgCl] and Sodium Nitrate [NaNO₃] are products.

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According to Law of Conservation of Mass, we know that :-

Mass of reactants = Mass of Products

Let the required mass of Silver Nitrate be 'x grams'.

⇒ x + 11.7 = 28.7 + 17

⇒ x + 11.7 = 45.7

⇒ x = 45.7 - 11.7

⇒ x = 34 g

Answer 2

Answer:

Required Answer :-

According to the question

We know that

The mass of reactants and Mass of products are in proportion.

So,

Let the silver nitrate be S

S + 11.7 = 28.7 + 17

11.7S = 45.7

45.7 - 11.7 = S

34 = S

Mass of silver nitrate = 34 gm