Question

What mass of slaked lime be required to decompose 4 gram of ammonium chloride also find the volume of ammonia gas formed in litres at STP

Answer 1

Ca(OH)

2 + 2NH

4 Cl ? CaCl

2 + 2NH

3 + 2H

2

O

40 + 2(1 + 16) 2( 14+4 +35.5) (40+2x35.5+) + 2(14 + 3) + 2(2+16)

74gm 107gm 111gm 34gm 36gm

1. 107 gms of NH

4 Cl is decomposed by 74 gms of Ca(OH)

2

Therefore, 4 gms of NH

4 Cl would be decomposed by ... 74 x 4/107

= 2.766 gms

2. 107 gms of NH

4 Cl produces 111 gms of CaCl

2

Therefore, 4 gms of NH

4 Cl would be produced by ... 111 x 4/107

= 4.15 gms

3. 107 gms of NH

4 Cl gives 34 gms of NH

3

Therefore, 4 gms of NH

4 Cl would give ... 34 x 4/ 107

= 1.271 gms

4. 107 gms of NH

4 Cl gives 36 gms of H

2

O

Therefore, 4 gms of NH

4

Cl would give ... 36 x 4/ 107

= 1.345 gms