Question

What mass of sodium chloride (NaCl) forms when 7.5 g of sodium carbonate (Na2CO3) reacts with a dilute solution of hydrochloric acid (HCl)?

Answer 1

What mass of sodium chloride (NaCl) forms when 7.5 g of sodium carbonate (Na2CO3) reacts with a dilute solution of hydrochloric acid (HCI)

8.3 is correct on E.D.G

Answer 2

When 7.5 g of sodium carbonate ($Na_2CO_3$) reacts with a dilute solution of hydrochloric acid (HCl), it yields 8.28 g of NaCl.

Given:

Mass of sodium carbonate = 7.5 g

To find:

Mass of sodium chloride (NaCl) = ?

Calculation:

• The chemical equation involved in the given reaction is as follows:

$Na_2CO_3+2HCl\rightarrow 2NaCl+H_2O+CO_2$

• In the above reaction, 1 mole of sodium carbonate gives 2 moles of sodium chloride.
• To find the grams and volume, the molecular weight of reactant as well as product must be calculated.
• Accordingly, the molecular mass is as follows:

$Na_2CO_3$

= 2 (Na) + 1 (C) + 3(O)

= 2 (23) + 1 (12) + 3 (16)

= 46 + 12 + 48

= 106 g/mol

$2 NaCl$

= 2 (23 + 35.5)

= 2 (58.5)

= 117 g/mol

Weight of sodium chloride formed:

As per the given chemical equation,

160 g of $Na_2CO_3$ gives = 117 g of NaCl     (1)

7.5 g of $Na_2CO_3$ gives = 'X' g of NaCl      (2)

When the equation 1 and 2 are cross multiplied it gives:

X × 106 = 117 × 7.5

X = $\frac{117\times7.5}{106}$

X = $\frac{877.5}{106}$

X = 8.28

Conclusion:

Thus it is inferred that 7.5 g of sodium carbonate ($Na_2CO_3$) reacts with a dilute solution of hydrochloric acid (HCl), it yields 8.28 g of NaCl.

Learn more about such concept

For the reaction A + 2B = C. 5 mole of A and 8 mole of B will produce

brainly.in/question/3754395

For the given reaction P4 + 5O2 gives P4O10.If 31 g of P4 is reacted with excess of oxygen,the percentage yield is 60% then the amount of product formed is

(1).42.6g

2)12.8g

3)71g

4)28.4g

brainly.in/question/4680599