Question

What mass of sodium chloride (NaCl) forms when 7.5 g of sodium carbonate (Na2CO3) reacts with a dilute solution of hydrochloric acid (HCl)?

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Finally, solve (remember significant figures):

Answer 1

Answer:

Given:

Mass of sodium carbonate = 7.5 g

To find:

Mass of sodium chloride (NaCl) = ?

Calculation:

The chemical equation involved in the given reaction is as follows:

In the above reaction, 1 mole of sodium carbonate gives 2 moles of sodium chloride.

To find the grams and volume, the molecular weight of reactant as well as product must be calculated.

Accordingly, the molecular mass is as follows:

= 2 (Na) + 1 (C) + 3(O)

= 2 (23) + 1 (12) + 3 (16)

= 46 + 12 + 48

= 106 g/mol

= 2 (23 + 35.5)

= 2 (58.5)

= 117 g/mol

Weight of sodium chloride formed:

As per the given chemical equation,

160 g of  gives = 117 g of NaCl     (1)

7.5 g of  gives = 'X' g of NaCl      (2)

When the equation 1 and 2 are cross multiplied it gives:

X × 106 = 117 × 7.5

X =  

X =  

X = 8.28

Conclusion:

Thus it is inferred that 7.5 g of sodium carbonate () reacts with a dilute solution of hydrochloric acid (HCl), it yields 8.28 g of NaCl.

Step-by-step explanation:

Answer 2

Answer: 8.3

Step-by-step explanation:

i got it right on edge  :)