Question

what mass of sodium chloride would be decomposed by 9.8g of sulphuric acid,if 12g of sodium bisulphate and 2.75g of hydrogen chloride were produced in a reaction assuming that the law of conservation of mass is true?​

Answer 1

Answer :-

The required mass of Sodium Chloride decomposed is 4.95 grams .

Explanation :-

We have :-

→ Mass of Sulphuric acid = 9.8 g

→ Mass of Sodium bisulphate = 12 g

→ Mass of Hydrogen Chloride = 2.75 g

________________________________

The skeletal chemical equation for the reaction taking place is :-

NaCl + H₂SO₄ → NaHSO₄ + HCl

• In this reaction, Sodium Chloride (NaCl) and Sulphuric acid (H₂SO₄) are reactants .

• While, Sodium bisulphate (NaHSO₄) and Hydrochloric acid (HCl) are products .

________________________________

Let the required mass of NaCl be "x" grams.

By using "Law of Conservation of Mass" we have it as :-

Mass of reactants = Mass of products

⇒ x + 9.8 = 12 + 2.75

⇒ x + 9.8 = 14.75

⇒ x = 14.75 - 9.8

⇒ x = 4.95 g

Answer 2

Answer:

4.95 g of Sodium chloride would be decomposed.

Explanation:

Given :

If 12g of Sodium bisulphate and 2.75g of Hydrogen Chloride were produced in a reaction assuming that the law of conservation of mass is true?​

To find :

What mass of sodium chloride would be decomposed by 9.8g of Sulphuric acid.

We have :

Mass of Sulphuric acid = 9.8 g

Mass of Sodium bisulphate = 12 g

Mass of Hydrogen Chloride = 2.75 g

Chemical equation :

NaCl + H₂SO₄ ➝ NaHSO₄ + HCl

Law of conservation of mass :

Mass can neither be created nor be destroyed but it can only be transformed from one form to another form, the mass of reactants must be equal to mass of products.

Mass of reactants = Mass of products :

Mass of Nacl + 9.8 = 12 + 2.75

Mass of Nacl + 9.8 = 14.75

Mass of Nacl = 14.75 - 9.8

Mass of Nacl = 4.95 g

∴ 4.95 g of Sodium chloride would be decomposed.