Question

What mass of sodium sulphate will react with 5.22g of barium chloride to produce 6.10g of sodium chloride and 2.8g of barium sulphate? name the law which govern your answer. write the balanced chemical equation

Answer 1

1. BaCl2 (aq) + Na2SO4 (aq) → BaSO4 (s) + 2NaCl (aq)

2. NaOH (aq) + HCl (aq) → NaCl (aq) + H2O (l)

 

Answer 2

Answer: 3.68 g of  sodium sulphate

Explanation: Every chemical equation follows the law of conservation of mass which states that the mass on the reactant side must be equal to the mass on the product side.

$Na_2SO_4+BaCl_2\rightarrow BaSO_4+2NaCl$

The mass of the products = 6.10g + 2.8g = 8.9g

Thus the mass of reactants should be =8.9g

The mass of  barium chloride is given to be =5.22 g Thus the mass of sodium sulphate =(8.9-5.22)g= 3.68g