Chemistry, asked by unaizasurroor, 1 year ago

What mass of sodium sulphate will react with 5.22g of barium chloride to produce 6.10g of sodium chloride and 2.8g of barium sulphate? name the law which govern your answer. write the balanced chemical equation

Answers

Answered by EmadAhamed
56
Na_2SO_4 + BaCl_2 --\ \textgreater \ BaSO_4 + 2NaCl

Let the mass of sodium sulphate be 'X'

X + Barium Chloride --> Barium Sulphate + Sodium Chloride

X + 5.22g --> 2.8g + 6.10g

X + 5.22g --> 8.9g

∴ X = 8.9g - 5.22g

X => 3.68g


Answered by BarrettArcher
11

Answer : The mass of sodium sulfate is, 3.68 grams. The name of the law is law of conservation of mass.

The balanced chemical reaction will be,

Na_2SO_4+BaCl_2\rightarrow 2NaCl+BaSO_4

Explanation :

The balanced chemical reaction will be,

Na_2SO_4+BaCl_2\rightarrow 2NaCl+BaSO_4

According to the law of conservation of mass, the mass of reactant must be equal to the mass of product.

In the given reaction, sodium sulfate and barium chloride are the reactants and sodium chloride and barium sulfate are the products.

As per law of conservation of mass,

Mass of reactant = Mass of product

\text{Mass of }Na_2SO_4+\text{Mass of }BaCl_2=\text{Mass of }NaCl+\text{Mass of }BaSO_4

\text{Mass of }Na_2SO_4+5.22g=6.10g+2.8g

\text{Mass of }Na_2SO_4=6.10+2.8-5.22

\text{Mass of }Na_2SO_4=3.68g

Therefore, the mass of sodium sulfate is, 3.68 grams. The name of the law is law of conservation of mass.

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