Question

What mass of sulfur is contained in a 250â‹…g mass of 98% sulfuric acid?

Answer 1

Answer:

82 g approx

Method:

no of moles of sulfuric acid = given mass of sulfuric acid/ molar mass of sulfuric acid

ie, no of moles of sulfuric acid = 250 / 98

                                                  = 2.56 moles

now, one mole of sulfuric acid contains 1 moles of Sulfur.

therefore, 2.56 mole of sulfuric acid will contain x moles

$x=\frac{1*2.56}{1}$

= 2.56 mole

Now mass of sulfur = no of moles * molar mass

                                = 2.56 * 32

                                =81.92

                                = 82 g approx

Answer 2

Answer:

82 g approx

Method:

no of moles of sulfuric acid = given mass of sulfuric acid/ molar mass of sulfuric acid

ie, no of moles of sulfuric acid = 250 / 98

                                                  = 2.56 moles

now, one mole of sulfuric acid contains 1 moles of Sulfur.

therefore, 2.56 mole of sulfuric acid will contain x moles

x=\frac{1*2.56}{1}x=11∗2.56

= 2.56 mole

Now mass of sulfur = no of moles * molar mass

                                = 2.56 * 32

                                =81.92

                                = 82 g approx