Question

What mass of sulphur dioxide contains the same number of molecules as are in 2.00 g of ammonia.?

Answer 1

Hello Mate!

Molecular formula of Ammonia = NH3

Molecular formula of Sulphur dioxide = SO2

No. of molecules of NH3 = No. of molecules of SO2

W in g/ W in g/mol × Avagrado number = W in g/ W in g/mol × Avagrado number

So, avagrado number get cancelled out.

W in g / W in g/mol = W in g / W in g/mol

W in g / ( 32 + 16 × 2 ) = 2 g / ( 14 + 1 × 3 )

W in g / 64 = 2 / 17

W in g = 2 × 64 / 17

W in g = 7.53 g

Hence, 7.53 g of sulphur dioxide contains the same number of molecules as are in 2.00 g of ammonia.

Have great future ahead!

Answer 2

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ıllıllıllıllıllıllı[ Your Answer ]ıllıllıllıllıllıllı

ȯ Given:

Mass of Ammonia = 2g

Molar mass of ammonia = (1 * 14) + (3 * 1) = 17

We know that, 17 g of ammonia will contain 6.022 * 10^23 molecules

Therefore 2 g of ammonia will contain,



= 0.708 * 10^23 molecules

Molar mass of sulphur dioxide = (1 * 32) + (2 * 16) = 64

We know that 64 g of sulphur dioxide will contain 6.022 * 10^23 molecules

Therefore, 0.708 * 10^23 molecules will weigh



= 7.52 g