Question

What mass of water will change its temperature by 3 °C when 525 J of heat is added to it? The specific heat of water is 4.18 J/g°C​

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

Based on the information you've provided, we know the following variables:

Δ

T

=

3

o

C

Q

= 525 J

C

=

4.8

J

g

×

o

C

All we have to do is rearrange the equation to solve for m. This can be accomplished by dividing both sides by

C

and

Δ

T

to get m by itself like this:

m

=

Q

Δ

T

×

C

Now, we just plug in the known values:

m

=

525

J

3

oC

×

4.8

J

g

×

oC

m

=

36.5

g

Explanation:

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