Question

What mass of ZnCl2 can be prepared from the reaction of 3.27 grams of zinc with 3.30 grams of HCl? Zn +2HCl ----> ZnCl2 + H2 *
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Answer 1

Answer:

Explanation:Zn. + 2 HCl ----------> ZnCl2. + H2

Mass of Zn in mole = 3.27/ 65.38= 0.050010.... mol

Mass of HCl in mole = 3.3/ 73= 0.044....mol

Hence, limiting reagent is HCl

Molar mass of ZnCl2= 136.38g

Let mass of ZnCl2 be x

x = 3.3*136.38÷ 73 = 6.165...

So, mass of ZnCl2 is 6.17 g