Question

what minimum effort is needed to lift a load of 150N using a lever whose mechanical advantage is 1.5 ​

Answer 1

Given,

Mechanical Advantage (M.A) = 1.5

Load (L) = 150 N

∴ M.A = L/E

= 1.5 = 150/E

= 1.5E = 150

= E = 100 N

The Effort (Minimum) will be 100 N.

I hope this helps.

Answer 2

Answer:

The Effort (Minimum) will be 100 N.