Question

What minimum effort is needed to lift a load of 150N using a lever whose mechanical advantage is 1.5N?​
Answer fast

Answer 1

Answer:

In Class III lever, the effort E is in between the fulcrum F and the load L. So, the effort arm is always smaller than the load arm. Hence, M.A. < 1.

Answer 2

Explanation:

MA= load/effort

effort= load/MA

=150 N/1.5

=100 N

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