What minimum must be added to 2 x cube minus 3 X square + 6 X + 7 to the resulting polynomial will be divisible by x square - 4 x + 8
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The minimum value that must be added to 2x³ - 3x² + 6x + 7 so that the resulting polynomial is completely divisible by x² - 4x + 8 is -(2x+3).
We must add the remainder when 2x³ - 3x² + 6x + 7 is divided by x² - 4x + 8 to 2x³ - 3x² + 6x + 7 to make it completely divisible.
After solving using long division method , Remainder = -(2x+3)
So -(2x+3) must be added to the polynomial to make the resultant polynomial completely divisible by x² - 4x + 8.
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