what minimum must be added to 2x² – 3x² + 6x + 7
so that the resulting polynomial will be
divided
by
se2
- 4x + 8?
Answers
Answer:
-10x+33
Step-by-step explanation:
divide p(x) by g(x)
Step-by-step explanation:
Given what minimum must be added to 2x² – 3x² + 6x + 7
so that the resulting polynomial will be
divided
Dividing the polynomial we get
2x + 5
---------------------------------------------------------------------------------
X^2 – 4x + 8) 2x^3 – 3x^2 + 6x + 7
2x^3 – 8x^2 + 16x
-----------------------------------------------------------------------------------
5x^2 – 10x + 7
5x^2 – 20 x + 40
----------------------------------------------------------------------------
10 x - 33
So – (10x - 33) should be added
Reference link will be
https://brainly.in/question/15928118