Question

what must be added 1760 to make it a perfect square also find the square root of the resultant after additing
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Answer 1

Answer:

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Step-by-step explanation:

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$\sqrt{1760} = 41.95 \\ so \: we \: take \: {42}^{2} \\ {42}^{2} = 1764 - - - - - (1)\\ {41}^{2} = 1760 - - - - - (2) \\ so \: we \: add \: 4 \: in \: (1) \: to \: get \: a \: perfect \: square$

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