What must be added 5x²-3x+1 to get 3x³-7²+8
Answers
Answered by
3
Answer:
From the question, the required expression is
=(3x 3−7x 2 +8)−(5x 2−3x+1)=3x
3−7x 2 +8−5x 2+3x−1=3x
3−12x 2+3x+7
Therefore, 3x
3−12x 2+3x+7
must be added to 5x
2 −3x+1 to get 3x 3 −7x 2 +8 .
Answered by
0
Answer:
What must be added 5x²-3x+1 to get 3x³-7²+8
Required ans is
(3x³-7²+8) - (5x²-3x+1)
=3x³-7²+8 - 5x²+3x-1
=3x³ - 5x² + 3x +8 -1 - 7²
=3x³ - 5x² + 3x +8 -1 - 49
=3x³ - 5x² + 3x -42
Step-by-step explanation:
But if question is What must be added 5x²-3x+1 to get 3x³-7x²+8
Then required ans is
(3x³-7x²+8) - (5x²-3x+1)
=3x³-7x²+8 - 5x²+3x-1
=3x³ -7x²- 5x² + 3x +8 -1
=3x³ - 12x² + 3x +7 (ans)
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