Math, asked by ak415805186, 1 month ago

What must be added 5x²-3x+1 to get 3x³-7²+8

Answers

Answered by krista00
3

Answer:

From the question, the required expression is

=(3x 3−7x 2 +8)−(5x 2−3x+1)=3x

3−7x 2 +8−5x 2+3x−1=3x

3−12x 2+3x+7

Therefore, 3x

3−12x 2+3x+7

must be added to 5x

2 −3x+1 to get 3x 3 −7x 2 +8 .

Answered by drssagrawal
0

Answer:

What must be added 5x²-3x+1 to get 3x³-7²+8

Required ans is

(3x³-7²+8) - (5x²-3x+1)

=3x³-7²+8 - 5x²+3x-1

=3x³ - 5x² + 3x +8 -1 - 7²

=3x³ - 5x² + 3x +8 -1 - 49

=3x³ - 5x² + 3x -42

Step-by-step explanation:

But if question is    What must be added 5x²-3x+1 to get 3x³-7x²+8

Then required ans is

(3x³-7x²+8) - (5x²-3x+1)

=3x³-7x²+8 - 5x²+3x-1

=3x³ -7x²- 5x² + 3x +8 -1

=3x³ - 12x² + 3x +7    (ans)

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