Question

what must be added in 2/7 to get 8/3?​

Answer 1

Answer:

Solution :

let the required number be x

2/7 + x = 8/3

=>x = 8/3-2/7

=>x =( 56-6)/21

=>x = 50/21

hence the required number is 50/21

Answer 2

$\huge\mathfrak{Answer:}$

Given:

• We have been given two numbers 2/7 and 8/3.

To Find:

• We need to find a number that must be added to 2/7 to get 8/3.

Solution:

Let the number to be added to 2/7 to get 8/3 be x.

According to the question, We have

$\sf{ \dfrac{2}{7} + x = \dfrac{8}{3} }$

$\implies\sf{x = \dfrac{8}{3} - \dfrac{2}{7} }$

Taking LCM = 21, we have

$\implies\sf{ x = \dfrac{7 \times 8 - 3 \times 2}{3 \times 7} }$

$\implies\sf{ x = \dfrac{56 -6 }{21} }$

$\implies\sf{ x = \dfrac{50}{21}}$

Hence, the required number is 50/21.