Question

what must be added in 4/7 to get 8/3?​

Answer 1

Answer:

solution:

let the required number be x

4/7 +x = 8/3

=>x = 8/3-4/7

=>x = (56-12)/21

=>x = 44/21

hence the required number is 44/21

Answer 2

$\huge\mathfrak{Answer:}$

Given:

• We have been given two rational numbers 4/7 and 8/3.

To Find:

• We need to find a number that must be added to 4/7 to get 8/3.

Solution:

Let the number that must be added to 4/7 to get 8/3 be x.

According to the question, we have

$\sf{ \dfrac{4}{7} + x = \dfrac{8}{3} }$

$\implies\sf{x = \dfrac{8}{3} - \dfrac{4}{7} }$

Taking LCM as 21, we have

$\implies\sf{ x = \dfrac{(7 \times 8) - (3 \times 4)}{7 \times 3} }$

$\implies\sf{ x = \dfrac{56 - 12}{21} }$

$\implies\sf{ x = \dfrac{44}{21}}$

Hence, the required number is 44/21.