Question

What must be added to 2^10 to get 2^11

Answer 1

Answer:

2^10 x 2

= 2^(10+1).... a^m x a^n = a^(m+n)

=2^11

hope that helps:)

Step-by-step explanation:

Answer 2

Answer:

1024 must be added to 2^10 to get 2^11.

Step-by-step explanation:

Given two term is ${2}^{10}$ and ${2}^{11}$

Now we know,

${x}^{y} =$ y times x is multiplied by x

So,

${2}^{10} = 1024 \\ and \: {2}^{11} = 2048$

We want to find what must be added to

${2}^{10}$ get ${2}^{11}$

Therefore we should add $(2048 - 1024) = 1024$

Hence request answer is 1024.

This is a problem of Algebra.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

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2) https://brainly.in/question/1169549