What must be added to 2a3-3a2+4a-5 so that the sum will be a3+3a2+3a+1
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answer :-
a3+6a2-1a- 4
Step-by-step explanation:
let be the added no. x
= a3+3a2+3a+1 -( 2a3-3a2+4a-5 )
= a3+3a2+3a+1 - 2a3 + 3a2 - 4a -5
= a3 -2a3 + 3a2 +3a2+3a-4a +1 -5
= a3+6a2-1a- 4
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