Math, asked by ParkJimin777, 4 months ago

what must be added to 2m^2 — 3mn + 3n ^2 to get 5m2 + 2mn + 7n^2?

Answers

Answered by bmeena2505
9

let the added number be x.

A.T.P,

2m²-3mn+3n²+x = 5m²+2mn+7n²

x = 5m²+2mn+7n²-2m²+3mn-3n²

x = 3m²+5mn+4n²

Answered by unicorn276
4

Step-by-step explanation:

196 is given 2 times so we can write 196^2 same with 104.

Let 196 be a and 104 be b.

Converting into variable form

 {a}^{2}  -  {b}^{2}

We know that

( {a}^{2}  -  {b}^{2} ) = (a + b) - (a - b)

Now, putting values in (a+b) (a-b)

(196+104) (196-104)

300 × 92

27600

Now, dividing 27600 by 92, we get

300.

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