Math, asked by tatwawadinetra, 1 month ago

What must be added to (2x^2 - 3x -8x) to get (3x^2 +x+6)​

Answers

Answered by JigyashaJain
3

Answer:

x² + 12x + 6

Step-by-step explanation:

Let the number be y.

According to question,

(2x² - 3x -8x) + y = (3x² +x+6)

y = (3x² +x+6) - (2x² - 3x -8x)

y = 3x² + x + 6 - (2x² - 11x)

y = 3x² + x + 6 - 2x² + 11x

y = x² + 12x + 6

(x² + 12x + 6) should be added to (2x² - 3x - 8x) to get (3x² +x+6).

Answered by IIMASTERII
3

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