Question

What must be added to 2x^2-3x-9 to get 3x^2+x+6?

Answer 1

Answer:

x²+4x+17

Step-by-step explanation:

2x²-2-3x-9 (Equation 1)    3x²+x+6(Equation 2)

=2x²-3x-11

NOW, SUBTRACT  (EQUATION 1) FROM (EQUATION 2)

=(3x²+x+6)-(2x²-3x-11)

=x²+4x+17

Answer 2

Answer:

x^2-2x-3

Step-by-step explanation:

Let no. = x

x + 2x^2-3x-9 = 3x^2+x+6

x = 3x^2+x+6 - 2x^2-3x-9

x = x^2-2x-3

so, the no. is x^2-2x-3 must be added 2x^2-3x-9 to get 3x^2+x+6.