Question

What must be added to (2x+3)² - (3x+2)² to make it 5
Plz solve it The answer given in book is 5x² but I couldn't solve it​

Answer 1

Here is the solution. Hope it helps :)

Answer 2

Answer:

Question:-

• What must be added to (2x+3)² - (3x+2)² to make it 5

Solution:-

Let the unknown number be y

therefore according to your question

Substituting the values

(2x+3)²-(3x+2)²+y=5

using the identity

(a+b)²=a²+2ab+b²

[(2x)²+2•2x•3+(3²)]-[(3x)²+2•3x•2+(2²)]+y=5

(4x²+12x+9-9x²-12x-4)+y=5

Substituting then completely to R.H.S

that is

y= 5- (4x²+12x+9-9x²-12x-4)

y=5- (-5x²+5)

y= 5+5x²-5

Here cancelling both 5

that is

y=5x²

Therefore the number added to make the result 5 is

5x²

Verification:-

(2x+3)²-(3x+2)²+5x²=5

[(2x)²+2•2x•3+(3²)]-[(3x)²+2•3x•2+(2²)]+5x²=5

(4x²+12x+9-9x²-12x-4)+5x²=5

-5x²+5+5x²=5

5=5

L.H.S=R.H.S

hence verified

hope it helps

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