Math, asked by preetamjn451, 1 month ago

what must be added to 2x^3-8x^2-x+3 to obtain a polynomial which is exactly divisible by (x+2)

Answers

Answered by harshamr
0

Step-by-step explanation:

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Answered by gopalpvr
1

Step-by-step explanation:

given polynomial= p(x)= 2x^3-8x^2-x+3

divisor= x+2

remainder = p(-2)

= 2(-2)^3-8(-2)^2-(-2)+3

=-16-32+2+3

=-43

so we must add 43 to obtain it is divisible be x+2

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