what must be added to 2x^3-8x^2-x+3 to obtain a polynomial which is exactly divisible by (x+2)
Answers
Answered by
0
Step-by-step explanation:
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Answered by
1
Step-by-step explanation:
given polynomial= p(x)= 2x^3-8x^2-x+3
divisor= x+2
remainder = p(-2)
= 2(-2)^3-8(-2)^2-(-2)+3
=-16-32+2+3
=-43
so we must add 43 to obtain it is divisible be x+2
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