what must be added to 2x2-3xy+5y2 to get x2-xy-y2
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Step-by-step explanation:
Let p should be add to 2x ^2-3xy+5y^to get x^2xy-y ^2
( 2x^2-3xy+5y^2 ) +p=x^2-xy-y^2
Therefore
p=x^2-xy-y ^2-(2x^2-3xy+5y^2 )
=x^2-xy-y^2-2x^2+3xy-5y^2
= x^2+2xy-6y^2
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