what must be added to 3 x cube + x square - 22 X + 9 so that the resulting polynomial is exactly divisible by 3 X square + 7 x minus 6
Answers
2x + 3 should be added to 3x³ + x² - 22x + 9 so that resulting polynomial is exactly divisible by 3x² + 7x - 6
Step-by-step explanation:
x - 2
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3x² + 7x - 6 _| 3x³ + x² - 22x + 9 |_
3x³ + 7x² - 6x
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-6x² - 16x + 9
-6x² - 14x + 12
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-2x - 3
Remainder = -(2x + 3)
Remainder should be subtracted from the number to get exactly divisible
Hence -ve of remainder should be added
-(-(2x + 3)) = 2x + 3
2x + 3 should be added to 3x³ + x² - 22x + 9 so that resulting polynomial is exactly divisible by 3x² + 7x - 6
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Step-by-step explanation:
I hope you get your answer
