Math, asked by khanmunib067, 3 months ago

what must be added to 3a^3-3a^2+3a-1 to get a^3+3a^2-3a+1​

Answers

Answered by ManTTaniha
5

equation:_

3a³ - 3a² + 3a - 1 = 0

when we put the any value upon 0 , the resulting answer will be 0

Answer :

3a {}^{3}  - 3 {a}^{2}  + 3a - 1 = 0 \\  \\   {a}^{3} - 3a {}^{2} + 3a - 1 =  \frac{0}{3}  \\  \\    {a}^{3} - 3a {}^{2} + 3a - 1 =  0

0 = + 3a²- 3a + 1

+ 3a²- 3a + 1 = 0

all the best buddy

Answered by Anonymous
13

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equation:_

3a³ - 3a² + 3a - 1 = 0

when we put the any value upon 0 , the resulting answer will be 0

Answer :-

3a^3 - 3a^2 + 3a - 1 = 0a^3 - 3a^2+ 3a - 1 = 0/3

a^3 - 3a^2 + 3a - 1 = 0

3a3−3a2+3a−1=0a3−3a2+3a−1=30a3−3a2+3a−1=0

0 = a³+ 3a²- 3a + 1

a³+ 3a²- 3a + 1 = 0

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